Problem 145 Gondwanaland Telecom，電話收費

Problem 145 設定了一個收費表，用通話距離以及通話時段區分不同的收費價格，給你一段時間，要計算出個時段所用的分鐘數，以及通話費。

這題只要想得出方法來算個時段的分鐘數，就可以解得出來了，跨夜時段比較難算，其他大概就沒有甚麼問題了。

以下是主程式程式碼：

struct Converse
{
    char charge, telephone[8];
    int sHour, sMin, eHour, eMin;
};
void getTime (int sH, int sM, int eH, int eM);
struct Converse c;
float charging[5][3] = { {0.10, 0.06, 0.02},
                         {0.25, 0.15, 0.05},
                         {0.53, 0.33, 0.13},
                         {0.87, 0.47, 0.17},
                         {1.44, 0.80, 0.30} };
int dayTime, eveningTime, nightTime;                         
int main()
{   
    while (1)
    {
        scanf("%c",&c.charge);
        if (c.charge == '#') break;
        scanf("%s %d %d %d %d",c.telephone ,&c.sHour ,&c.sMin ,&c.eHour ,&c.eMin);
        int chargeIndex = c.charge - 'A';
        dayTime = 0, eveningTime = 0, nightTime = 0;
        
        if(c.sHour >= c.eHour && c.sMin >=  c.eMin)
            getTime(c.sHour, c.sMin, 24, 0) ,getTime(0, 0, c.eHour, c.eMin);
        else
            getTime(c.sHour, c.sMin, c.eHour, c.eMin);

        float money = (float)(dayTime * charging[chargeIndex][0]) + 
                      (float)(eveningTime*charging[chargeIndex][1]) +
                      (float)(nightTime*charging[chargeIndex][2]);

        printf("%10s%6d%6d%6d%3c%8.2f\n", c.telephone, dayTime, eveningTime, nightTime, c.charge, money);
        char ch = getchar();
    }    
    return 0;
}

接下來 getTime 函式就交給大家去寫了。

By David.K

p145題目連結
回ACM題庫目錄
回首頁