C 程式設計作業三，迴圈與隨機數應用：解題

/* C Programming Project 3 */
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <time.h>

int main(void)
{
    int dice = 0, currentPos = 0, roundNo = 0;
    int money = 10000; 
    int lucky; 
    char finger[3] = "↖"; 
    
    srand(time(NULL)); 
    while (roundNo < 3)
    { 
        printf("\n春分  機會  夏至\n\n");
        printf("命運   %s   川堂\n\n", finger);
        printf("冬至  大門  秋分\n");
        printf("================\n");
        printf("現存現金 %d 元\n\n", money);
        printf("按任意鍵來丟骰子..."); 
        getch();
        system("cls");
        dice = rand()%6 + 1;
        printf("骰子為 %d\n\n", dice); 
        currentPos += dice;
        if (currentPos/8 == 1)
            roundNo++;
        currentPos %= 8;
        switch(currentPos)
        {
            case 0:
                printf("由此過得2000元\n");
                money += 2000; 
                break;
            case 1:
                printf("機會：");
                lucky = rand()%4 + 1; 
                switch (lucky)
                {
                    case 1: 
                        dice = rand()%3 + 1; 
                        printf("前進 %d 格\n", dice);
                        currentPos += dice; 
                        break; 
                    case 2: 
                        dice = rand()%3 + 1; 
                        printf("後退 %d 格\n", dice);
                        currentPos -= dice; 
                        break; 
                    case 3: 
                        printf("損失 500 元\n");
                        money -= 500; 
                        break; 
                    case 4: 
                        printf("獲利 600 元\n");
                        money += 600; 
                        break; 
                } 
                break;
            case 2:
                printf("損失 1000元\n");
                money -= 1000; 
                break;
            case 3:
                printf("獲利 1500元\n");
                money += 1500; 
                break;
            case 4:
                printf("前進 二格\n");
                currentPos += 2; 
                break;
            case 5:
                printf("後退 二格\n");
                currentPos -= 2; 
                break;
            case 6:
                printf("損失 800元\n");
                money -= 800; 
                break;
            case 7:
                printf("命運：");
                lucky = rand()%4 + 1; 
                switch (lucky)
                {
                    case 1: 
                        dice = rand()%3 + 1; 
                        printf("前進 %d 格\n", dice);
                        currentPos += dice; 
                        break; 
                    case 2: 
                        dice = rand()%3 + 1; 
                        printf("後退 %d 格\n", dice);
                        currentPos -= dice; 
                        break; 
                    case 3: 
                        printf("損失 600 元\n");
                        money -= 600; 
                        break; 
                    case 4: 
                        printf("獲利 500 元\n");
                        money += 500; 
                        break; 
                } 
                break;
            default:
                break; 
        }

        switch(currentPos)
        {
            case 0:
                strcpy(finger, "↖");
                break;
            case 1:
                strcpy(finger, "↑");
                break;
            case 2:
                strcpy(finger, "↗");
                break;
            case 3:
                strcpy(finger, "→");
                break;
            case 4:
                strcpy(finger, "↘");
                break;
            case 5:
                strcpy(finger, "↓");
                break;
            case 6:
                strcpy(finger, "↙");
                break;
            case 7:
                strcpy(finger, "←");
                break;
            default:
                break; 
        }
    } 
    system("pause");
    return 0;
}

作業三題目
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