作業八：機器人駕駛(解答)

宣告一個迴圈，同時做讀取機器人走的方位與步數以及將字串拆解成陣列的動作，C#語言程式碼如下

for (i = 0; i < cases; i++)
{
   int m = int.Parse(Console.ReadLine());
   for (j = 0; j < m; j++)
   {
      string instruct = Console.ReadLine();
      string[] value = instruct.Split(' ');
      qus.Blue[i].MoveTo(value[0], value[1]);
      qus.Red[i].MoveTo(value[2], value[3]);
   }
}

計算方位與距離

double pointView = Math.Atan((qus.Blue[i].y - qus.Red[i].y) /
                  (qus.Blue[i].x - qus.Red[i].x)) * 180 / Math.PI;
double distance = Math.Sqrt((qus.Blue[i].x - qus.Red[i].x) * (qus.Blue[i].x - qus.Red[i].x) + 
                  (qus.Blue[i].y - qus.Red[i].y) * (qus.Blue[i].y - qus.Red[i].y));

最後判斷以一點為中心另一點是在哪個象限再決定是要加90&270或者減90&270

if ((qus.Red[i].x - qus.Blue[i].x) >= 0 && (qus.Red[i].y - qus.Blue[i].y) >= 0)
{
   Console.Write("Blue: {0:f3}, {1} Red: {2:f3}, {3}", distance, Math.Round(90 - pointView), distance, Math.Round(270 - pointView));
}
if ((qus.Red[i].x - qus.Blue[i].x) >= 0 && (qus.Red[i].y - qus.Blue[i].y) <= 0) {     Console.Write("Blue: {0:f3}, {1} Red: {2:f3}, {3}", distance, Math.Round(90 - pointView), distance, Math.Round(270 - pointView)); } if ((qus.Red[i].x - qus.Blue[i].x) <= 0 && (qus.Red[i].y - qus.Blue[i].y) >= 0)
{
   Console.Write("Blue: {0:f3}, {1} Red: {2:f3}, {3}", distance, Math.Round(270 - pointView), distance, Math.Round(90 - pointView));
}
if ((qus.Red[i].x - qus.Blue[i].x) <= 0 && (qus.Red[i].y - qus.Blue[i].y) <= 0) {     Console.Write("Blue: {0:f3}, {1} Red: {2:f3}, {3}", distance, Math.Round(270 - pointView), distance, Math.Round(90 - pointView)); } 

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